A sailboat starts from rest and accelerates at a rate of 0.21 m/s² over a distance of 280 m.

a. Find the magnitude of the boatâs final velocity.

b. Find the time it takes the boat to travel this distance.

Answer

given,

initial speed of boat, u = 0 m/s

acceleration of the boat, a = 0.21 m/s²

distance, s = 280 m

a) using equation of motion

v² = u² + 2 a s

v² = 0² + 2 x 0.21 x 280

v = √117.6

v = 10.84 m/s

Final speed of the boat is equal to 10.84 m/s

b) again using equation of motion

v = u + a t

10.84 = 0 + 0.21 x t

0.21 t = 10.84

t = 51.62 s

time taken by the boat to travel the distance is equal to 51.62 s.