A 1500-kg car doubles its speed from 50 km/h to 100 km/h. By how many times does the kinetic energy from the car's forward motion increase?

The kinetic energy increases 4 times

Explanation:

Given,

The mass of the car, m = 1500 Kg

The speed of the car doubles from 50 Km/h to 100 Km/h

The kinetic energy at 50 Km/h

K. E = ½mv²

= ½ x 1500 x 50²

= 1875000 J

The kinetic energy of the car at 100 Km/h

K. E = ½mv²

= ½ x 1500 x 100²

= 7500000 J

Hence, the final K. E is 4 times the initial K. E