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9 February, 11:02

A current of 55.9 mA flows in a silver wire of diameter 4.33 mm. Find the electric field strength inside the wire. The conductivity of silver is 6.25 * 10 7 Ω - 1 m - 1.

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  1. 9 February, 13:48
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    6.07 * 10^ (-5) N/C

    Explanation:

    Parameters given:

    Diameter = 4.33 mm

    Radius = 2.165 mm = 0.002165 m

    Conductivity, σ = 6.25 * 10 (Ωm) ^ (-1)

    Current, I = 55.9 mA = 0.0559 A

    Electric field Intensity, E, is given as:

    E = I/Aσ

    Where A = Area

    E = 0.0559 / (π*0.002165²*6.25*10^7)

    E = 0.0559/919

    E = 6.08 * 10^ (-5) N/C
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