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1 June, 20:01

A steel safe with mass M falls onto a concrete floor. Just before hitting the floor, its speed is vi. It hits the floor without rebounding, and ends up being d shorter than before. Find the magnitude of the (average) force exerted by the floor on the safe while it is being deformed. You can assume this force is a constant during the short time it takes for the safe to deform. Ignore the effects of gravity.

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  1. 1 June, 23:57
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    initial velocity, u = vi

    final velocity, v = 0

    distance = d

    mass of safe = M

    Use third equation of motion

    v² = u² + 2as

    0 = vi² - 2 ad

    a = vi²/2d

    Force, F = mass x acceleration

    F = M x vi²/2d

    F = Mvi²/2d
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