what is the force of friction between an 80kg box and the ground on Earth if the coefficient is 0.2?

160N

Explanation: When 80kg mass is one group. It's reaction force acting on a ground.

Weight of the object = 80*10

= 800 N

Here we are given cofficient of static friction its 0.2. It should be smaller than 1

Friction force = Reaction * Friction Cofficient

Reaction = 800N (Considering Vertical Equilibrium)

F = 800 * 0.2

F = 160N

Answer: 160N

Explanation: Fr = coefficient x mass x acceleration due to gravity

= 0.2x80x10=160N