An inductor in the form of an air-core solenoid contains 191 turns, is of length 17.9 cm, and has a cross-sectional area of 1.2 cm^2. The permeability of free space is 1.25664 * 10^-6 N/A^2. What is the magnitude of the uniform rate of change in current through the inductor that induces an emf of 205 µV? Answer in units of A/s.

Question

Physics

Bullwinkle

2 February, 14:58

An inductor in the form of an air-core solenoid contains 191 turns, is of length 17.9 cm, and has a cross-sectional area of 1.2 cm^2. The permeability of free space is 1.25664 * 10^-6 N/A^2. What is the magnitude of the uniform rate of change in current through the inductor that induces an emf of 205 µV? Answer in units of A/s.

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Answers (1)

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Jair Hatfield · Answer 1

The magnitude of the uniform rate of change in current through the inductor is 13.66 A/s.

Explanation:

To find the magnitude of the uniform rate of change in current through the inductor we will use the formula:

ΔI/Δt = e*l / μ0*N*A

Now, put all the given values in this formula and then you will get your answer,

ΔI/Δt = 205*10^-6*19.2 / 1.2566*10^-6*191*1.2

ΔI/Δt = 13.66 A/s.