If a 42kg rolling object slows from 11.5m/s to 3.33m/s how much work did friction do

Answer: 1608.39 J

Explanation: Given that the

mass M = 42kg

U = 11.5m/s

V = 3.33m/s

how much work did friction do

Work done = Force * distance

Work done = Ma * distance

But acceleration a = V/t

Work done = M * V/t * d

Work done = M * V * d/t

Where d/t = velocity

Therefore,

Work done = M * U * V

Work done = 42 * 11.5 * 3.33

Work done = 1608.39 J