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22 June, 14:57

A sled weighing 300 N is moved at constant speed over a horizontal floor by a force of 50 N applied parallel to the floor

determine the coefficient of friction between the sled and the floor

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  1. 22 June, 16:10
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    If the sled is moving at a constant speed, that mean there needs to be an equal but opposite force countering the 50 N force. This opposite force is friction, and is equal to the weight times a factor:

    F = n*W

    Let n be the coefficient of friction.

    Now you simply fill in the formula and you get:

    50 N = n*300N or n = 50N / 300N = 1/6

    So, the final answer is 1/6 or 0.1667
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