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8 August, 01:00

a runner moves 2.38 m/s north. She accelerates at 0.310 m/s^2 at a - 62.0 degree angle. How many seconds later is she running directly east

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  1. 8 August, 02:35
    0
    8.70 s

    Explanation:

    Given (in the y direction):

    v₀ = 2.38 m/s

    v = 0 m/s

    a = 0.310 sin (-62.0°) m/s²

    Find: t

    v = at + v₀

    0 m/s = (0.310 sin (-62.0°) m/s²) t + (2.38 m/s)

    t = 8.70 s
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