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10 March, 19:47

What is the current in a circuit with a 12.0 V battery and a 4.0 Ω resistor? 0.3 A 3.0 A 8.0 A

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Answers (2)
  1. 10 March, 20:06
    0
    B) 3.0 A
  2. 10 March, 20:59
    0
    3 amperes

    Explanation:

    V = IR

    Where

    V = voltage

    I = current and

    R = resistor

    Given

    V = 12.0v

    R = 4.0 ohms

    Therefore

    12.0 = I x 4.0

    Divide both sides by 4.0

    12.0/4.0 = I x 4.0/4.0

    3 = I

    I = 3 amperes
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