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3 June, 15:07

A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this time, the train moves a

distance of

meters.

+1
Answers (1)
  1. 3 June, 15:40
    0
    Answer: 400m

    Explanation:

    In theory and for a train with an initial velocity the expression reads

    Eq. (1) : Velocity = Initial Velocity + Acceleration*Time v = v0 + at

    We also know that the distance expression for a train with a initial velocity that then accelerates reads

    Eq. (2) : Distance = 0.5 * (Velocity + Initial Velocity) * Time d = 0.5 * (v0 + v) * t

    Now subsituting in Eq. (1) for all known value we can obtain the Velocity after the acceleration of the train as such:

    v = 20 + (4 * 10)

    v = 20 + 40

    v = 60m/s

    Then plugging in the value for v above, in Eq. (2) we get:

    d = 0.5 * (20 + 60) * 10

    d = 0.5 * (80) * 10

    d = 400m
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