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9 December, 16:58

An aircraft is in a steady level turn at a flight speed of 200 ft/s and a turn rate about the local vertical of 5 deg/s. Thrust frm the engine is along the flight direction. Given the weight of the aircraft as 50,000 lb and L/D of 10, determine the lift, drag and thrust required for the given equilibrium flight. Assume g = 32.2 ft/s

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  1. 9 December, 19:30
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    L = 4166.66 N and D = 46296.29 N and T = 96047.34 N

    Explanation:

    given,

    flight speed = 200 ft/s

    turn rate = 5 deg/s

    weight of aircraft = 50000 lb

    L/D = 10

    for equilibrium in the horizontal position

    w - L cos ∅ - D sin ∅ = 0 ... (1)

    D cos ∅ - L sin ∅ = 0 ... (2)

    L/D = tan ∅ = 10

    ∅ = 84.29°

    50000 - L cos 84.29° - D sin 84.29° = 0

    D cos 84.29° - L sin 84.29° = 0

    on solving the above equation we get

    L = 4166.66 N and D = 46296.29 N

    thrust force calculation:

    T = W sin ∅ + D

    = 50000*sin 84.29 + 46296.29

    T = 96047.34 N
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