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4 December, 08:55

A uniform cubical crate is 0.740 m on each side and weighs 600 N. It rests on the floor with one edge against a very small, fixed obstruction. At what least height above the floor must a horizontal force of magnitude 330 N be applied to the crate to tip it?

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  1. 4 December, 10:21
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    H = 0.673

    Explanation:

    given,

    side of cubical crate = 0.74

    weight of the crate = 600 N

    magnitude of force = 330 N

    the Horizontal distance of its Center of mass

    = 0.74/2

    = 0.37

    Let the required Height be H

    By Balancing the Torques, we get

    H x 330 N = 0.37 x 600

    330 H = 222

    H = 0.673

    hence, the height above the floor where force is acting is equal to 0.673 m
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