A uniform 40-N board supports two children weighing 500 N and 350 N. If the support is at the center of the board and the 500-N child is 1.5 m from its center, How far is the 350-N child from the center?

b = 2.14 m

Explanation:

Given that

Weight of the board, wt = 40 N

Wight of the first children, wt₁=500 N

Weight of the second children, wt₂ = 350 N

The distance of the 500 N child from center, a = 1.5 m

lets take distance of the 350 N child from center = b m

Now by taking the moment about the center of the board

We know that moment = Force x Perpendicular distance from the force

wt₁ x a = wt₂ x b

500 x 1.5 = 350 x b

b = 2.14 m

Therefore the distance of the 350 N weight child from the center is 2.14 m.