Two flat conductors are placed with their inner faces separated by 17 mm. If the surface charge density on one of the inner faces is 108 pC/m2 and the other inner face - 108 pC/m2, what is the magnitude of the electric potential difference between the

two conductors?

Question

Physics

Demarion Dudley

20 July, 13:26

Two flat conductors are placed with their inner faces separated by 17 mm. If the surface charge density on one of the inner faces is 108 pC/m2 and the other inner face - 108 pC/m2, what is the magnitude of the electric potential difference between the

two conductors?

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Answers (1)

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Dalia · Answer 1

electric field between plates

= surface charge density / ε₀

= 108 x 10⁻¹² / 8.85 x 10⁻¹² (ε₀ = 8.85 x 10⁻¹²)

= 12.20 V / m

Electric potential diff

= electric field x distance between plates

= 12.20 x 17 x 10⁻³ V

= 0.207 Volt

Two flat conductors are placed with their inner faces separated by 17 mm. If the surface charge density on one of the inner faces is 108 pC/m2 and the other inner face - 108 pC/m2, what is the magnitude of the electric potential difference between thetwo conductors?

Two flat conductors are placed with their inner faces separated by 17 mm. If the surface charge density on one of the inner faces is 108 pC/m2 and the other inner face - 108 pC/m2, what is the magnitude of the electric potential difference between the

two conductors?