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8 April, 20:43

The density of ice is 917kg/m3 and the density of sea water is 1025kg/m3. A swimming polar bear climbs onto a piece of floating ice that has a volume of 5.2m3. What is the weight of the heaviest bear that the ice can support without sinking completely beneath the water?

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  1. 8 April, 21:58
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    W_Bear = 5503.7 N

    Explanation:

    This problem should use the principle here that gives the thrust and Newton's equilibrium equation

    B - W_ice - W_bear = 0

    W_bear = B - W_ice

    The thrust is given by

    B = ρ _water g V

    Ice weight

    W_ice = m g

    Density is

    ρ_ice = m / V

    W_ice = ρ_ice V g

    We replace

    W_bear = ρ_water g V - ρ_ice g V

    W_Bear = g V (ρ_water - ρ_ice)

    calculate

    W_bear = 9.8 5.2 (1025 - 917)

    W_Bear = 5503.7 N
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