Ask Question
26 June, 02:01

answer A vertical spring stretches 3.4 cm when a 8-g object is hung from it. The object is replaced with a block of mass 26 g that oscillates in simple harmonic motion. Calculate the period of motion.

+2
Answers (1)
  1. 26 June, 03:30
    0
    0.695s

    Explanation:

    From Hooke's law, the restoring force is given has

    F = - ky ... 1

    Where F is the force, y is the spring displacement and k force constant of the spring.

    Also recall,

    F=mg ... 2

    Where m is the mass of object, g is the acceleration due to gravity.

    Equating 1 and 2

    Ky = mg

    Given that g=9.8m/s2, y is 3.4cm and g is 8g

    K*3.4/100m = 8/1000kg * 9.8m/s2

    K = (0.008kg * 9.8m/s2) : 0.034

    K = 0.0784:0.035

    K=2.24N/m

    Mass ofvthe second object is 25g = 0.025kg

    Period of oscillation T

    T=2π√m/k

    T=2*3.142√0.025/2.24

    T=6.284√0.0111

    T=0.659seconds
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “answer A vertical spring stretches 3.4 cm when a 8-g object is hung from it. The object is replaced with a block of mass 26 g that ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers