How much work did the movers do (horizontally) pushing a 41.0-kgkg crate 10.6 mm across a rough floor without acceleration, if the effective coefficient of friction was 0.60?

W=2.60 J

Explanation:

Given that

m = 41 kg

d = 10.6 mm

Coefficient of friction = 0.6

Friction force, Fr=μ m g

Fr = 0.6 x 41 x 10 N (take g = 10 m/s²)

Fr = 246 N

We know that work done by a force given as

W = F. d

Now by putting the values

W = 246 x 10.6 x 10 ⁻³ J

W=2.60 J

Therefore the work done by movers in the horizontal direction will be 2.60 J. The mover does the work against the friction force.