A small block with mass 0.200 kg is released from rest at the top of a frictionless incline. The block travels a distance 0.202 m down the incline in 2.00 s. The 0.200 kg block is replaced by a 0.400 kg block. If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?

Answer: The block of 0.4 Kg travel the same distance that the block of

0.2 Kg

Explanation: Considering the second newton law, we have the following

F = m*a

F = P*sin (θ) where θ is the angle for the incline

so mg sin (θ) = m*a

a=g sin (θ)

both block have the same acceleration in the inclined plane so travel the same distance independent of its mass.