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29 July, 14:34

A weight of 20.0 N hangs motionless from a spring, with a spring constant of 65.0 N/m. How far is the spring stretched from its original length?

0.130 m

0.308 m

0.769 m

3.25 m

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Answers (2)
  1. 29 July, 17:23
    0
    0.308 m

    Explanation:

    Force = spring constant * change in length

    F = k * Δx

    F = 20 N

    k = 65 N/m

    Δx = ? m

    20 = 65 * Δx

    20/65 = Δx

    Δx = 0.308 m
  2. 29 July, 17:46
    0
    Extension = force/spring constant.

    extension = 20/65

    extension = 0.308 m
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