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30 August, 02:16

A sample container of carbon monoxide occupies a volume of 435 ml at a pressure of 785 torr and a temperature of 298 k. What would its temperature be if the volume were changed to 265 ml at a pressure of 785 torr?

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  1. 30 August, 03:49
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    181.54 K

    Explanation:

    From gas laws, we know that v1/t1 = v2/t2 where v and t represent volume and temperatures, 1 and 2 for the first and second container. Making t2 the subject of the formula then

    T2=v2t1 / v1

    Given information

    V1 435 ml

    V2 265 ml

    T1 298K

    Substituting the given values then

    T2=265*298/435=181.54 K
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