A system does 203 J of work on its environment and gains 96.8 J of heat in the process. Find the change in the internal energy of (a) the system and (b) the environment.

a) The change in the internal energy of the system = - 106.2 J

b) The change in the internal energy of the environment = 106.2 J

Explanation:

Given that

The work done by system, W = 203 J

Heat gain, Q = 96.8 J

We know that

Q = W + ΔU

ΔU = Change in the internal energy

W=Work done

Q=Heat

Now by putting the values in the above equation we get

96.8 = 203 + ΔU

ΔU = 96.8 - 203 J

ΔU = - 106.2 J

The change in the internal energy of the system = - 106.2 J

The change in the internal energy of the environment = 106.2 J