Using the Bohr model, what is the ratio of the energy of the nth orbit of a triply ionized beryllium atom (Be3+, Z = 4) to the energy of the nth orbit of a hydrogen atom (H) ? Enth orbit, Be / Enth orbit, H

16

Explanation:

solution:

by taking the ratio of the energy E_n, be of the nth orbit of a beryllium atom

Z_be=4 to the energy E_n, h of the nth orbit of a hydrogen (Z_h=1) atom gives

E_n, B/E_n, H = - (2.18*10^-18) * Z^2_BE / - (2.18*10^-18) * Zh^2/n^2

=Z^2_BE+/Z^2_H

= (4) ^2 / (1) ^2

= 16