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16 November, 14:01

A body 'X' of weight 400N placed on the left side of a seesaw 250cm away from the pivot. A body 'Y' of weight 300N is placed on right side of seesaw 3.5m away from pivot. Has the seesaw attained equilibrium? Show your work?

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  1. 16 November, 15:19
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    No.

    Explanation:

    if it's in equilibrium then the torque or moment of inertia on both sides should cancel.

    Torque is a vector quantity, force times distance.

    When doing these, make sure your units are the same by changing centimeters to meters first.

    Left side is 400N * (-2.5m) = - 1000 Nm

    Right side is 300N * (3.5m) = 1050 Nm

    -1000 Nm + 1050 Nm does not equal zero so there's a torque on the teeter and it will rotate clockwise. The system is not yet in equilibrium.
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