A turtle, moving at a constant velocity of 0.9 m/s due East, is in a race with a rabbit, who runs at a moderate speed of 9 m/s. When the turtle is 45 m from the finish line, the rabbit begins taunting the turtle by running from the turtle to the finish line (without crossing it) and back to the turtle. The rabbit continues going back and forth between the turtle and the finish line until the turtle crosses the finish line. About how many meters does the rabbit travel as the turtle travels that last 45 m? Assume the rabbit always runs at 9 m/s and doesn't lose any time changing direction.

Question

Physics

Jorden Howe

31 August, 03:24

A turtle, moving at a constant velocity of 0.9 m/s due East, is in a race with a rabbit, who runs at a moderate speed of 9 m/s. When the turtle is 45 m from the finish line, the rabbit begins taunting the turtle by running from the turtle to the finish line (without crossing it) and back to the turtle. The rabbit continues going back and forth between the turtle and the finish line until the turtle crosses the finish line. About how many meters does the rabbit travel as the turtle travels that last 45 m? Assume the rabbit always runs at 9 m/s and doesn't lose any time changing direction.

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Answers (1)

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Dinosaur · Answer 1

d = 450m

Explanation:

we know that:

V = d/t

where V is the velocity, d the distance and t the time.

so:

the turtle run at 0.9m/s a distance of 45m:

replacing v by 0.9 m/s and d by 45 m, we get:

V = d/t

0.9 = 45/t

solving for t:

t = 45/09 = 50 s

Now, using the same equation, the time that the turtle takes to travel 45 meters and the velocity of the rabbit, we get:

V = d/t

(9) = d / (50)

Solving for d:

d = 9*50 = 450m

it means that the rabbit travel 450m at the same time that the turtle travel 45m.