A ball is thrown vertically downward at 10 m/s. what is it's speed 1s and 2s later

20 m/s

30 m/s

Explanation:

Given:

v₀ = - 10 m/s

a = - 9.8 m/s²

When t = 1 s:

v = v₀ + at

v = (-10 m/s) + (-9.8 m/s²) (1 s)

v = - 19.8 m/s

When t = 2 s:

v = v₀ + at

v = (-10 m/s) + (-9.8 m/s²) (2 s)

v = - 29.6 m/s

Rounded to one significant figures, the speed of the ball at 1 s and 2 s is 20 m/s and 30 m/s, respectively.