A particle is projected at an angle 60 degrees to the horizontal with a speed of 20m/s. (i) calculate total time of flight of the particle. (i) speed of the particle at its maximum height

Time of flight=3.5 seconds

Speed at maximum height is 0

Explanation:

Φ=60°

initial velocity=u=20m/s

Acceleration due to gravity=g=9.8 m/s^2

Total time of flight=T

Final speed=v

question 1:

T = (2 x u x sinΦ) / g

T = (2 x 20 x sin60) / 9.8

T = (2 x 20 x 0.8660) / 9.8

T=34.64/9.8

T=3.5 seconds

Question 2

Speed at maximum height is 0