If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current for the Pentium Prescott? Note: power is defined as the product of voltage and current. Answer as a percentage of the original voltage between 0 and 100 with up to two decimal places.

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Physics

Picasso

15 October, 08:27

If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current for the Pentium Prescott? Note: power is defined as the product of voltage and current. Answer as a percentage of the original voltage between 0 and 100 with up to two decimal places.

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Jakob Kane · Answer 1

power P = v x I

v is voltage and I is current,

ln P = ln v + ln I

differentiating

Δp/p x 100 = x Δv/v x 100 (I is constant)

10 = Δv/v x 100

10 = percentage change in voltage

percentage change in voltage = 10