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27 October, 09:37

A former student of mechanics wishes to weigh himself but has access only to a scale a with capacity limited to 120 lbs and a small 20-lb spring dynamometer

b. with the rig shown he discovers that when he exerts a pull on the rope so that b registers 16 lb, the scale a reads 100 lb. what is his correct weight?

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  1. 27 October, 12:32
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    The answer to the question is

    The correct weight of the former student = 116 lbf

    Explanation:

    To solve the question, we list out the known variables as follows

    Capacity of the scale = 120 lbs

    Capacity of the spring dynamometer = 20 lbs

    Reading on the scale = 100lb

    Reading on the spring dynamometer = 16 lb

    at equilibrium, sum of forces = 0

    Therefore weight of former student = reaction forces of the scale + the reaction force of the spring dynamometer = 100lb + 16 lb = 116 lb

    The correct weight = 116lb weight or 52.62 kg

    Converting to weight which is a force = mass * acceleration = 52.62 kg * 9.81 m/s² =

    516.2 N = 116 lbf
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