The fermer is a bone in the leg whose minimum cross-sectional area is about 4.0104m2. A compres-sional force in excess of 6.8104N will fraction thebone. a) Find the maximum stress that this bone canwithstand. b) What is the strain that exists under amaximum stress condition?

a) 1.70N/m^2

b) 4.8 * 10^-6

Explanation:

Parameters given:

Cross sectional area = 4.0104m^2

Maximum Force = 6.8104N

a) Maximum Stress = Maximum Force/Area

Maximum Stress = 6.810/4.0104

Maximum Stress = 1.70N/m^2

b) Strain = Stress/Young's Modulus

Young's modulus of the outer surface of bone has been measured to be 20.7 GPa i. e. 2.07 * 10^7Pa

Strain = 1.7 / (2.07 * 10^7)

Strain = 4.8 * 10^-6

Strain is dimensionless.