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7 August, 06:28

a 0.0250 kg sock spins in a dryer of radius 0.225 m once every 0.304s. how much centripetal force acts on the sock? (unit=N)

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  1. 7 August, 08:10
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    Fc = 1.77N

    Explanation:

    Lets write down everything we have:

    m = 0.0250kg

    r = 0.225m

    Fc = ? (centripetal force)

    T = 0.304s. (period formula is seconds / cycle. 0.304s / 1 cycle, which is equal to 0.304s per cycle. This is the time)

    Fc = mv^2 / r

    We dont have v, so we can use the formula for constant velocity; v = d/t

    v = d/t

    distance is 2πr, since that is the circumferance of a circle

    v = 2πr / t

    v = 2π*0.225 / 0.304

    v = 4.65m/s

    Now plug everything into Fc formula;

    fc=mv^2 / r

    Fc = (0.0250kg) (4.65) ^2 / 0.304

    Fc = 1.77N
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