A 1.20x10^3 kilogram car is traveling east at 25 meters per second. the brakes are applied and the car is brought to rest in 5.00 seconds answer

What is the magnitude of the horizontal net force that is required to bring it to a halt in a distance of 50.0m

F = 7500 N

Explanation:

given,

mass of the car, m = 1200 Kg

initial speed of the car, v = 25 m/s

final speed of car = 0 m/s

time in which car is at rest, t = 5 s

distance = 50 m

Force = ?

using equation of motion for the calculation of acceleration.

v² = u² + 2 a s

0² = 25² + 2 x a x 50

100 a = - 625

a = - 6.25 m/s²

negative sign shows deceleration of the car

now, force calculation

F = m a

F = 1200 x 6.25

F = 7500 N

hence, net force is equal to F = 7500 N