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11 January, 05:54

A rectangular-shaped vegetable garden next to a barn is to be fenced on three sides with 120 total feet of fencing. Find the dimensions of the garden that will maximize the area.

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  1. 11 January, 08:57
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    The dimensions of the garden are

    Length = 30 ft

    Width = 60 ft

    Explanation:

    Given dа ta:

    Total length of the fencing, L = 120 ft

    Now,

    let the length of the garden be 'x' feet

    width of the garden be 'y' feet

    Now, the area A for rectangle is given as:

    A = xy

    Now,

    given y + 2x = 120 ft

    or

    y = 120 - 2x

    substituting the value of y in the formula for area, we get

    A = x * (120 - 2x)

    or

    A = 120x - 2x²

    Now, for maximizing the area

    dA/dx = 0

    therefore, differentiating the formula for area with respect to side x

    we get

    dA/dx = 120 - 4x = 0

    or

    4x = 120

    or

    x = 30 ft

    hence,

    y = 120 - 2x

    or

    y = 120 - 2 (30)

    or

    y = 60 ft

    Thus, the dimensions of the garden are

    Length = 30 ft

    Width = 60 ft
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