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12 March, 06:13

Calculate the specific

heat capacity of substance having mass 5 kg whose

temperature increase from 15°C to 25°C by the supply of

19 KJ

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Answers (1)
  1. 12 March, 07:27
    0
    Answer: c = 0.38 J / g °C

    Explanation: Use the equation Q = mcΔT and derive to solve for c.

    c = Q / mΔT

    First convert 19 KJ to joules

    19 kJ x 1000 J / 1 kJ = 19000 J

    Then convert 5 kg to grams

    5 kg x 1000 g / 1 kg = 5000 g

    After that substitute the following variables into the equation.

    c = 19000 J / 5000 g (25 - 15) = 0.38 J / g°C
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