At what displacement of a sho is the energy half kinetic and half potential?

Displacement = 0.707A

Explanation:

To solve for the displacement we know that

Potential energy PE = 1/2Total energy (Etotal)

Therefore 1/2kx^2 = 1/2 (1/2KA^2)

Solving for x we have

x^2 = √A^2/2

x = A/√2

x = 0.707A