a 2.4*10^2 N force is pulling an 85 kg refrigerator across a horizontal surface. the force acts at an angle of 20.0 above the surface. the coefficient of kinetic friction is. 200, and the refrigerator moves a distance of 8.00 m. find (a) the work dont by the pulling force, and (b) the work done by the kinetic frictional force

a) 1800 Joules

b) - 1201.47Joules

Explanation:

Workdone by pulling force = F (cos angle) * s

Where s = displacement

W = 240N (cos20°) * 8m

W = 1800 Joules

b) The frictional force will be opposite the displacement, therefore the angle will be 180°

Workdone by kinetic frictional force Fs=Fn * coefficient of kinetic friction

W = [ (85*9.8) - 240sin20°) ] * [0.200cos180*8]

W = (833-82.08) * (-1.6)

W = 750.92 * (-1.6)

W=-1201.47Joules

a) The work done by pulling force, W = 1804.21 joules

b) The work done by the kinetic frictional force is, w = 1332.8 J

Explanation:

Given,

The pulling force, Fₐ = 2.4 x 10² newton

The mass of the refrigerator, m = 85 Kg

The angle of pulling force acting to the surface, ∅ = 20°

The coefficient of kinetic friction is, μₓ = 0.200

The distance covered by the refrigerator, s = 8 m

The force acting in the direction parallel to the surface is given by

F = Fₐ cos∅

∴ F = 2.4 x 10² x cos 20°

=225.53 N

The work done by the pulling force is given by

W = F · S

= 225.53 N x 8 m

= 1804.21 joules

The work done by the pulling force, W = 1804.21 joules

The kinetic friction force is given by the formula

Fₓ = μₓ · η

Where

μₓ - coeficient of kinetic frictoin

η - Normal force, (mg)

∴ Fₓ = 0.200 x 85 x 9.8

= 166.6 N

The work done by the kinetic frictional force is given by

w = Fₓ · S

= 166.6 N x 8 m

= 1332.8 J

Hence, the work done by the kinetic frictional force is, w = 1332.8 J