Ask Question
29 July, 22:26

A force F of magnitude 2x^3 is applied to stop a particle moving with an initial velocity of v0. The particle travels from x=0 to x = D in coming to a stop after the force F is applied. The work done by F is:a) 1/2 D^3b) - D^4c) D^4d) 2D^3e) - D^3f) - 1/2 D^4g) 1/2D^4h) - 1/2D^3

+5
Answers (1)
  1. 30 July, 02:05
    0
    Given that

    F=2x³

    Work is given as

    The range of x is from x=0 to x=D

    W=-∫f (x) dx

    Then,

    W=-∫2x³dx from x=0 to x=D

    W = - 2x⁴/4 from x=0 to x=D

    W=-2 (D⁴/4-0/4)

    W=-D⁴/2

    W=1/2D⁴

    The correct answer is F
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A force F of magnitude 2x^3 is applied to stop a particle moving with an initial velocity of v0. The particle travels from x=0 to x = D in ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers