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8 February, 23:08

What change in volume results if 0.06 L of gas is cooled from 33.0 C to 5.00 C?

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  1. 8 February, 23:14
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    -0.005 L

    Explanation:

    Ideal gas law:

    PV = nRT

    where P is absolute pressure,

    V is volume,

    n is number of moles,

    R is the gas constant,

    and T is absolute temperature.

    If P and n are held constant, then:

    nR/P = nR/P

    V/T = V/T

    Given V₁ = 0.06 L, T₁ = 33.0 C = 306.15 K, and T₂ = 5.00 C = 278.15 K:

    0.06 / 306.15 = V / 278.15

    V = 0.055

    The change in volume is:

    0.055 L - 0.06 L = - 0.005 L
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