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5 March, 07:50

An astronomical telescope has its two lenses spaced 82.1 cmcm apart. If the objective lens has a focal length of 78.0 cmcm, what is the magnification of this telescope

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  1. 5 March, 09:34
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    19.02

    Explanation:

    Let Fo = focal length of the objective and

    Fe = focal length of the eyepiece

    Fo + Fe = 82.1 cm where Fo = 78.0 cm

    Fe = 82.1 cm - 78.0cm = 4.1 cm

    magnification = Fo / Fe = 78 / 4.1 = 19.02
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