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12 June, 01:39

The height of an object dropped from the top of a 64-foot building is given by h (t) = -16t^2+64. How long will it take the object to hit the ground?

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  1. 12 June, 05:33
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    1.86 s

    Explanation:

    Given the expression

    h (t) = - 16t² + 64 ... Equation 1

    Where h = height of the object, t = time it will take the object to hit the ground.

    Given: h = 64 foot.

    We have to concert from foot to meters

    If 1 foot = 0.3048 meters

    Then, 64 foot = 0.3048*64 = 19.51 meters.

    We substitute the value of h into equation

    119.51 = - 16t²+64

    -16t² = 199.51-64

    -16t² = 55.51

    t² = 55.51/-16

    t² = 3.469

    t = √3.469

    t = 1.86 s.

    Hence it will take the object 1.86 s to hit the ground.
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