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5 February, 20:49

A battery operating a large flashlight produces a current of 2 amperes in a lightbulb that has a resistance of 2.4 ohms. The voltage of the battery is:

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  1. 5 February, 21:27
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    Voltage of the battery = 4.8 volt

    Explanation:

    It is given that the flashlight produces a current of 2 ampere

    So current i = 2A

    And the resistance R = 2.4 ohm

    We have to find the voltage of the battery

    According to ohm's law voltage of the battery is given by = current * resistance

    So voltage = 2*2.4 = 4.8 volt

    The voltage of the battery depends on the current and resistance.
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