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21 August, 00:09

A girl of mass 55 kg throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of 25 m/s and it bounces back with this same speed. The ball is in contact with the wall 0.050 s. What is the magnitude of the average force exerted on the wall by the ball?

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  1. 21 August, 02:52
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    Magnitude of the average force exerted on the wall by the ball is 800N

    Explanation:

    Given

    Contact Time = t = 0.05 seconds

    Mass (of ball) = 0.80kg

    Initial Velocity = u = 25m/s

    Final Velocity = 25m/s

    Magnitude of the average force exerted on the wall by the ball is given by;

    F = ma

    Where m = 0.8kg

    a = Average Acceleration

    a = (u + v) / t

    a = (25 + 25) / 0.05

    a = 50/0.05

    a = 1000m/s²

    Average Force = Mass * Average Acceleration

    Average Force = 0.8kg * 1000m/s²

    Average Force = 800kgm/s²

    Average Force = 800N

    Hence, the magnitude of the average force exerted on the wall by the ball is 800N
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