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21 June, 14:56

What is the lowest frequency that will resonate in an organ pipe 2.00 m in length, closed at one end? The speed of sound in air is 340 m/s.

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  1. 21 June, 17:27
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    42.5 Hz.

    Explanation:

    The fundamental frequency of a closed pipe is given as

    f₀ = v/4l ... Equation 1

    Where f₀ = lowest frequency, v = speed of sound in air, l = length of the organ pipe

    Given: v = 340 m/s, l = 2.00 m.

    Substitute into equation 1

    f₀ = 340 / (4*2)

    f₀ = 340/8

    f₀ = 42.5 Hz.

    Hence the smallest frequency that will resonant in the organ pipe = 42.5 Hz.
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