Give the approximate bond angle for a molecule with an octahedral shape. A) 109.5°B) 180°C) 120°D) 105°E) 90°

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Physics

Branden

13 November, 08:33

Give the approximate bond angle for a molecule with an octahedral shape. A) 109.5°B) 180°C) 120°D) 105°E) 90°

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Abagail Hale · Answer 1

90°

Explanation:

A molecule with an octahedral shape has a central atom bonded by six atoms or groups of atoms with no lone pairs of electron. The ideal bond angles is 90°. Examples of compounds with octahedral shape are sulfur hexafluoride SF₆ and molybdenum hexacarbonyl Mo (CO) ₆

For a molecule with an octahedral shape:

Number of Electron Groups = 6

Electron-Group Geometry = octahedral

Number of Lone Pairs = 0

Valence Shell Electron Pair Repulsion (VSEPR) Notation = AX₆E₀ or AX₆

Ideal Bond Angles = 90°