A 91 kg water skier floating in a lake is pulled from rest to a speed of 13m/s in a distance of 23m. Wha is the bet force exerted on the skier, assuming his acceleration is constant?

F = 1183 N

Explanation:

Given,

The mass of the skier, m = 91 Kg

The initial speed of the skier, u = 0 m/s

The final speed of the skier, v = 13 m/s

The distance traveled by the skier, d = 23 m

The velocity and displacement relation is given by the formula

v = d/t m/s

∴ t = d/v s

Substituting the given values in the above equation

t = 23 / 13

= 1.769 s

Therefore, the acceleration of the skier,

a = (v-u) / t

= (23 - 0) / 1.769

= 13 m/s²

The force acting on the skier is given by the formula

F = ma N

= 91 Kg x 13 m/s²

= 1183 N

Hence, the bet force exerted on the skier, assuming his acceleration is constant is, F = 1183 N