What quantity of heat is required to raise the temperature of 0.1 kg of water by 1⁰c

0.418 Joules

Explanation:

Recall that the formula:

Heat Added = Specific heat x mass x change in temperature

or

Q = mcΔT

in this case we are given that m = 0.1 kg, ΔT = 1°C (aka 1 kelvin).

we also know that c for water is 4.1813 J/kg-K

substituting this into the formula

Q = 0.1 x 4.1813 x 1 = 0.41813 = 0.418 Joules (3 dec pl)