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21 May, 23:57

In an automobile collision, a 44-kilogram passenger moving at 15 meters per second is brought to rest by an air bag during a 0.10-second time interval. What is the magnitude of the average force exerted on the passenger during this time?

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  1. 22 May, 01:47
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    6,600N

    Explanation:

    According to second law of motion, Force = mass * acceleration

    If acceleration = change in velocity/time = 15/0.10

    Acceleration = 150m/s²

    Given mass = 44kg

    Force = 44 * 150

    Force = 6,600N

    Magnitude of the average force exerted on the passenger during this time is 6,600N
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