The charge on a parallel plate capacitor is 7.68 C, and the plate is connected to a 9.0 V battery. What is the capacitance of the capacitor?

A. 8.5x10^-7 pF

B. 1.1x10^-6 pF

C. 8.5x10^5 pF

D. 6.9x10^7 pF

Charge on a capacitor = (capacitance) x (voltage)

7.68 Coulomb = (capacitance) x (9.0 V)

Capacitance = (7.68 Coul) / (9.0 V)

Capacitance = 0.83 Farad

Apparently, the " 10^something " after the 7.68 C got lost.

If the charge is actually 7.68 microcoulombs, then the answer is (A).