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6 November, 02:14

A flute player hears four beats per second when she compares her note to an 880 Hz tuning fork (note A). She can match the frequency of the tuning fork by pulling out the "tuning joint" to lengthen her flute slightly. What was her initial frequency?

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  1. 6 November, 04:16
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    884Hz

    Explanation:

    Beats is the absolute difference between two frequencies therefore

    Beats = f1-f2

    4=f1-880

    F1=880+4

    F1=884Hz
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