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27 September, 13:35

A tennis ball is thrown straight up with an initial speed of 20.5 m/s. It is caught at the same distance about ground as it is thrown.

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  1. 27 September, 15:36
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    Answer: 21.4 m

    Time in air = 2 x 2.09 = 4.18 s

    Explanation:

    v (f) ² = v (i) ² + 2as

    Take up as positive direction

    0 = 20.5² - 2 * 9.8s

    s = 21.4 m

    So the ball rises to 21.4 m

    (b) v (f) = v (i) + at

    0 = 20.5 - 9.8t

    t = 2.09 s [this is the time to max height]

    Because the ball returns to exactly the same height from which it was thrown, time up = time down

    So time in the air = 2 x 2.09 = 4.18 s
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